Answer:
Step-by-step explanation:
The given expression is:
[tex]\frac{2}{x^2-36}-\frac{1}{x^2+6x}[/tex]
On simplifying the above equation, we get
=[tex]\frac{2}{(x+6)(x-6)}-\frac{1}{x(x+6)}[/tex]
=[tex]\frac{2x}{x(x+6)(x-6)}-\frac{x-6}{x(x-6)(x+6)}[/tex]
=[tex]\frac{2x-x+6}{x(x+6)(x-6)}[/tex]
=[tex]\frac{(x+6)}{x(x+6)(x-6)}[/tex]
=[tex]\frac{1}{x(x-6)}[/tex]
Therefore, the values of a, b , c, d, e, f and g are 6, 2, 6, 2, 6, 6 and 1 respectively.
