A car turns a corner that has a radius of 5 m and experiences a centripetal acceleration of 20 m/s². If the radius of turn were increased to 10 m, calculate the centripetal acceleration.

Respuesta :

The centripetal acceleration is given by:
[tex]a_c = \frac{v^2}{r} [/tex]
where
v is the velocity of the object
r is the radius of the trajectory

Initially, the car has an acceleration of [tex]a_c = 20 m/s^2[/tex] and the radius of its trajectory is [tex]r=5 m[/tex], so its velocity is
[tex]v= \sqrt{a_c r}= \sqrt{(20 m/s^2)(5 m)} =10 m/s [/tex]

Then the radius is increased to r=10 m, so the new centripetal acceleration is:
[tex]a_c = \frac{v^2}{r}= \frac{(10 m/s)^2}{10 m}= 10 m/s^2 [/tex]

Answer:

10

Explanation: