evelynn2001 evelynn2001

08-05-2018
Mathematics

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x2+y2-4+2y-11=0 what are the center and radius of the circle?

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mathstudent55 mathstudent55

08-05-2018

[tex] x^2 + y^2 - 4x + 2y - 11 = 0 [/tex]

You need to complete the square for both x and y.

[tex] x^2 - 4x + y^2 + 2y = 11 [/tex]

[tex] x^2 - 4x + 4 + y^2 + 2y + 1 = 11 + 4 + 1 [/tex]

[tex] (x - 2)^2 + (y + 1)^2 = 16 [/tex]

[tex] (x - 2)^2 + (y + 1)^2 = 4^2 [/tex]

The center is (2, -1).
The radius is 4.

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