Respuesta :
Hi there!
The answer is C.
[tex] {x}^{2} - 14x + 45 = (x - 9)(x - 5)[/tex]
To find our answer we are looking for 2 integers. The sum of the integers must be -14 (since it must be equal to the number before the variable x). The product of both integers must be 45. Now we can conclude we are looking for the numbers -9 and -5.
[tex] - 9 + - 5 = - 9 - 5 = - 14 \\ - 9 \times - 5 = 45[/tex]
(Remember that multiplying 2 negatives makes you end up with a positive.)
~ Hope this helps you!
The answer is C.
[tex] {x}^{2} - 14x + 45 = (x - 9)(x - 5)[/tex]
To find our answer we are looking for 2 integers. The sum of the integers must be -14 (since it must be equal to the number before the variable x). The product of both integers must be 45. Now we can conclude we are looking for the numbers -9 and -5.
[tex] - 9 + - 5 = - 9 - 5 = - 14 \\ - 9 \times - 5 = 45[/tex]
(Remember that multiplying 2 negatives makes you end up with a positive.)
~ Hope this helps you!