Using Hooke's law, F subscript s p r i n g end subscript equals k increment x, find the elastic constant of a spring that stretches 2 cm when a 4 newton force is applied to it.

A. 1/2 N/cm

B. 2 N/cm

C. 4 N/cm

D. 8 N/cm

Respuesta :

Let's rewrite Hook's law:
[tex]F=-kx[/tex]
where
F is the force
k is the spring's constant
x is the compression/elongation of the spring

Neglecting the sign (since we are not interested in the direction of the force), we can re-arrange the formula and use the data of the problem to find the spring constant:
[tex]k= \frac{F}{x}= \frac{4 N}{2 cm}=2 N/cm [/tex]

Therefore, the correct answer is B) 2 N/cm.

Answer:

b. 2N/cm

Explanation:

i took the test