contestada

The center of a circle is at (2, −5) and its radius is 12.

What is the equation of the circle?

(x−2)2+(y+5)2=144
(x+2)2+(y−5)2=144
(x+2)2+(y−5)2=24
(x−2)2+(y+5)2=24

Respuesta :

glendyrivera64
The answer is the first one. (x−2)2+(y+5)2=144.  Hope this helps.

The equation of the circle is given by (x-h)^2 + (y-k)^2 = r^2 where (h,k) represent the center of the circle and r represents the radius

From the question , we have been given (h,k) = (2,-5) and r =12

(x-2)^2 + (y-(-5))^2 = 12^2

The two minuses in the second term cancel out and give a plus. (-*- = +)

(x-2)^2 + (y+5)^2 = 144

So, the equation of the circle is:

(x-2)^2 + (y+5)^2 = 144 (Option A)


Otras preguntas