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PLEASE HELP!

The center of a circle is at (2, −5) and its radius is 12.

What is the equation of the circle?

(x−2)2+(y+5)2=144
(x+2)2+(y−5)2=144
(x+2)2+(y−5)2=24
(x−2)2+(y+5)2=24

Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{2}{ h},\stackrel{-5}{ k})\qquad \qquad radius=\stackrel{12}{ r} \\\\\\\ [x-2]^2+[y-(-5)]^2=12^2\implies (x-2)^2+(y+5)^2=144[/tex]

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