Respuesta :

The correct answer is: True

Explanation:
1. [tex]log_a1 = 0[/tex] (Straightforward)
2. [tex]log_aa = 1 [/tex] (log to base of itself is always 1)
3. [tex]log_a \frac{1}{a} = log_aa^{-1} = -1(1) = -1[/tex] (Using log power property)

Hence the correct option is True.