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Tripp and Rico are two dogs. Tripp weighs exactly 35 pounds more than Rico. Together, they weigh exactly 49 pounds. How much does each dog weigh? Please use Two-step equations!!!! plz, help!

Respuesta :

twvogels
Call the weights of the two dogs [tex]t[/tex] and [tex]r[/tex].

We know that Tripp weights 35lbs more than Rico, or:
[tex]t=r+35[/tex]

We also know that the total weight of both dogs is 49lbs.:
[tex]t+r=49[/tex]

Now, by substitution:
[tex](r+35)+r=49[/tex]
[tex]2r+35=49[/tex]
[tex]2r+35-35=49-35[/tex]
[tex]2r=14[/tex]
[tex]r=\frac{14}{2}[/tex]
[tex]r=7[/tex]
Rico weighs 7lbs.

Then:
[tex]t=r+35[/tex]
[tex]t=7+35[/tex]
[tex]t=42[/tex]
Tripp weighs 42lbs.

To check our work:
[tex]t+r=49[/tex]
[tex]42+7=49[/tex]
[tex]49=49[/tex]  CHECK!

Using a system of equations, it is found that Tripp weighs 42 pounds and Rico weighs 7 pounds.

What is a system of equations?

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: Tripp's weight.
  • Variable y: Rico's weight.

Tripp weighs exactly 35 pounds more than Rico, hence:

x = 35 + y.

Together, they weigh exactly 49 pounds, hence:

x + y = 49

35 + y + y = 49

2y = 14 -> y = 7

x = 35 + y -> x = 42

Hence, Tripp weighs 42 pounds and Rico weighs 7 pounds.

To learn more about a system of equations, you can check https://brainly.com/question/24342899

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