The work done by a force is given by:
[tex]W=Fd \cos \theta[/tex]
where
F is the magnitude of the force
d is the distance covered by the object
[tex]\theta[/tex] is the angle between the direction of the force and the direction of motion
In our problem, [tex]F=5200 N[/tex], [tex]d=25 m[/tex] and [tex]\theta=0[/tex] (because the force is parallel to the direction of motion), so the work done by the crane is
[tex]W=(5200 N)(25 m)(\cos 0^{\circ})=1.3 \cdot 10^5 J[/tex]
