First, we can calculate the power used by the lamp, which is given by the product between the voltage and the current:
[tex]P=VI=(120 V)(0.5 A)=60 W[/tex]
Now, we know that the energy used is the product between the power and time. The time interval is 1 minute, which corresponds to 60 s, therefore the energy used during this time is
[tex]E=Pt=(60 W)(60 s)=3600 J[/tex]
Therefore, A) is the correct answer.
