Answer:
[tex]80\ yd[/tex]
Step-by-step explanation:
Let
x------> the distance between the parking garage and the theater
we know that
In a right triangle
Applying the Pythagoras Theorem
[tex]c^{2} =a^{2}+b^{2}[/tex]
where
c is the hypotenuse
a,b are the legs of the triangle
In this problem we have
[tex]c=100\ yd, a=60\ yd, b=x\ yd[/tex]
substitute and solve for x
[tex]100^{2} =60^{2}+x^{2}[/tex]
[tex]x^{2}=100^{2}-60^{2}[/tex]
[tex]x^{2}=6,400[/tex]
[tex]x=80\ yd[/tex]
