A) the slope of distance vs time is speed:
i) from 09:00 to 09:11 it is increasing velocity positively and steadily by going away from the origin.
ii) the car speeds up by going away from the origin with constant velocity.
iii) the car does not have any movement stationary in 9m.
iv) it car is dropping speed, going toward the origin.
b) distance= 9m+6m=15m
c) i) slope= velocity= (9-0)/(24)= 3/8 km/h
ii) velocity = (6-4)/(19)=2/19 km/h
