Respuesta :
[tex]4^{3x+7}= \dfrac{1}{16} [/tex]
[tex]4^{3x+7}= \dfrac{1}{4^2} [/tex]
[tex]4^{3x+7}= 4^{-2}[/tex]
Equate the power and solve x:
3x + 7 = -2
3x = - 9
x = -3
Answer: x = -3
[tex]4^{3x+7}= \dfrac{1}{4^2} [/tex]
[tex]4^{3x+7}= 4^{-2}[/tex]
Equate the power and solve x:
3x + 7 = -2
3x = - 9
x = -3
Answer: x = -3