When 80 g of sodium hydroxide, naoh, are dissolved in enough water to make 500 ml of solution, the molarity of the solution is — a 1 m b 2 m c 4 m d 8 m?

Answer is: molarity of sodium hydroxide solution is c. 4 M.
m(NaOH) = 80.0 g.
n(NaOH) = m(NaOH) ÷ M(NaOH).
n(NaOH) = 80 g ÷ 40 g/mol.
n(NaOH) = 2 mol.
V(NaOH) = 500 mL ÷ 1000 mL/L = 0.5 L.
c(NaOH) = n(NaOH) ÷ V(NaOH).
c(NaOH) = 2 mol ÷ 0.5 L.
c(NaOH) = 4 mol/L.

n - amount of substance.

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aliasger2709 aliasger2709 · Answer 2 · 2022-06-06T12:23:52+02:00

The molarity of the solution indicates the concentration of the solute dissolved in the solution. The molarity of the 500 mL solution is 4M. Thus, option c is correct.

What is molarity?

Molarity is the ratio of the moles of the solute that were dissolved in a solvent to make a liter of solution. The molar concentration is calculated as:

Molarity (M) = moles ÷ volume

Given,

The mass of sodium hydroxide = 80 gm

Volume of solution = 500 mL

Molar mass of sodium hydroxide = 39.997 g/mol

Moles of sodium hydroxide is calculated as:

Moles = mass ÷ molar mass

= 80 ÷ 40

= 2 moles

Molarity is calculated as:

M = n ÷ V

= 2 moles ÷ 0.5 L

= 4 M

Therefore, option c. the molarity of sodium hydroxide solution is 4 M.

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