The acid dissociation constant for an acid dissolved in water is equal to the ____.
a. equilibrium constant
b. equilibrium constant times the concentration of water
c. equilibrium constant divided by the concentration of water
d. equilibrium constant times the equilibrium constant of water

Respuesta :

equilibrium constant times the concentration of water. - 100% guaranteed correct

Answer:The correct answer is option b.

Explanation:

[tex]HA+H_2O\rightleftharpoons A^-+H_20^+[/tex]

The equilibrium constant expression is given as:

[tex]K_{eq}=\frac{[A^-][H_3O^+]}{[HA][H_2O]}[/tex]

[tex]K_a=K_{eq}\times [H_2O]=\frac{[A^-][H_3O^+]}{[HA]}[/tex]

The acid dissociation constant is product of equilibrium constant and concentration of water.

Hence,from the given options the correct answer is option b.