Explanation:
According to the mole concept, 1 mole of an atom contains [tex]6.022 \times 10^{23}[/tex] atoms or molecules.
Therefore, we can calculate the number of atoms present in 0.10 mol of [tex]PtCl_{2}(NH_{3})_{2}[/tex] as follows.
[tex]0.10 mol \times 6.022 \times 10^{23}[/tex] atoms
= [tex]0.6022 \times 10^{23}[/tex]
= [tex]6.022 \times 10^{22}[/tex]
Therefore, we can conclude that there are [tex]6.022 \times 10^{22}[/tex] atoms present in 0.10 mol of [tex]PtCl_{2}(NH_{3})_{2}[/tex].
