Answer:
Option B is correct.
add 4 times the second equation to 3 times the first equation
Step-by-step explanation:
Given the system of equation:
[tex]2x - 4y = 6[/tex] ......[1]
[tex]-3x + 3y =12[/tex] .....[2]
Multiply equation [1] by 3 we get;
[tex]3(2x-4y) = 3 \cdot 6[/tex]
Using distributive property; [tex]a\cdot (b+c) = a\cdot b+ a\cdot c[/tex]
6x - 12y = 18 .......[3]
Multiply equation [2] by 4 we get;
[tex]4(-3x+3y) = 4 \cdot 12[/tex]
Using distributive property we get;
-12x + 12y = 48 ......[4]
Add equation [3] and [4] to eliminate y and solve for x;
(6x -12y) + ( -12x +12y ) = 18 + 48
6x - 12y -12x + 12y = 66
Combine like terms;
6x - 12x = 66
or
-6x = 66
Simplify:
x = -11
Therefore, the operation which could be used to eliminate the y-variable and find the value of x is;
add 4 times the second equation to 3 times the first equation.
Answer:
Option B
Step-by-step explanation:
Given is a system of two equations as
[tex]2x − 4y = 6 \\−3x + 3y = 12[/tex]
To solve them using elimination:
Elimination method is the method of making coefficients of one variable numerically equal
IN the given system we have -4 as coefficient for y in I equation and 3 for y in II equation.
To make them numerically equal with opposite signs we can multiply I equation by 3 and II by 4
WE get
[tex]6x-12y =18\\-12x+12y=48[/tex]
Now if we add these two we are able to eliminate y from the system
Adding gives
[tex]-6x=66\\x=-11[/tex]
So option B is right
