Respuesta :
For this case we have to factorize the following trinomials as the product of two binomials.
We have then:
a2 + a - 20
(a + 5) (a-4)
a2 - 9a + 20
(a-5) (a-4)
a2 - 8a - 20
(a-10) (a + 2)
a2 - 12a + 20
(a-10) (a-2)
a2 - 19a - 20
(a-20) (a + 1)
We have then:
a2 + a - 20
(a + 5) (a-4)
a2 - 9a + 20
(a-5) (a-4)
a2 - 8a - 20
(a-10) (a + 2)
a2 - 12a + 20
(a-10) (a-2)
a2 - 19a - 20
(a-20) (a + 1)
Answer:
a2 + a - 20
(a + 5) (a-4)
a2 - 9a + 20
(a-5) (a-4)
a2 - 8a - 20
(a-10) (a + 2)
a2 - 12a + 20
(a-10) (a-2)
a2 - 19a - 20
(a-20) (a + 1)
Step-by-step explanation: