For a we have:
x ^ 2 + 6x = x (x + a) = x (x + 6)
a = 6
For b we have:
b = 2
For c we have:
x-c = x-6
c = 6
For d and e we have:
bx-x + c = dx-x + e
b = d = 2
c = e = 6
For f we have:
dx-x + e = x (d-1) + e = x (2-1) + e = x + e = x + f
e = f = 6
For g we have:
(x + f) / (x + 6) = (x + 6) / (x + 6) = g = 1
g = 1
