Respuesta :

gmany
[tex]-9 > -2-\dfrac{3}{4}v\ \ \ |+2\\\\-7 > -\dfrac{3}{4}v\ \ \ |change\ both\ sides\\\\\dfrac{3}{4}v > 7\ \ \ \ |\cdot\dfrac{4}{3}\\\\v > \dfrac{28}{3}\to v\in\left(9\frac{1}{3};\ \infty\right)[/tex]