For this case we have the following system of equations:
1/3 y - 5 = 2x
y = 15 + 6x
The equations are linearly dependent, that is, there is a scalar that allows us to write an equation as a linear combination of the other.
We multiply the equation (1) by a scalar, which will be 3:
3 * (1/3 y - 5) = 3 * (2x)
Rewriting:
y-15 = 6x
y = 15 + 6x
Answer:
Therefore, if there is a solution, then there are infinite solutions.
