The path of a rocket ship is given by the parametric equations x(t)=3t and y(t)=4t^2+1, where t is the time in seconds after launch. Where is the ship after 10 seconds?
(3, 4)
(3, 5)
(30, 401)
(30, 501)
We just have to plug t=10 into the formulas for the coordinates of the point. And we find that x(10) = 3*10=30 and y(10)=4*100+1=401. The answer is (30, 401)
