Respuesta :

√10910.44030650 <--- Answer

Distance=(x2x1)2+(y2y1)2

((−1)(2))2+((−5)(5))

That check sign is the square root, since they wouldnt let me put it in...
[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~ 2 &,& 5~) % (c,d) &&(~ -1 &,& -5~) \end{array} \\\\\\ d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(-1-2)^2+(-5-5)^2} \\\\\\ d=\sqrt{(-3)^2+(-10)^2}\implies d=\sqrt{109}[/tex]