A metal washer is made by cutting out a circle 13.2 mm in diameter from a larger circle. To the nearest tenth, what is the area of the washer?

547.1 mm2
972.6 mm2
60.8 mm2
243.3 mm2

A metal washer is made by cutting out a circle 132 mm in diameter from a larger circle To the nearest tenth what is the area of the washer 5471 mm2 9726 mm2 608 class=

Respuesta :

To find this answer you will subtract the area of the smaller circle from the area of the larger circle.

Area of Big - Area of Small
(pi x r^2)    - (pi x r^2)
(3.14 x 11^2) - (3.14 x 6.6^2)
379.94 square mm - 136.78 square mm = 243.16 square mm

The answer is approximately 243.3 square mm.



Answer: [tex]243.3\ mm^2[/tex]

Step-by-step explanation:

Given: The diameter of smaller circle = 13.2 mm

Then the radius of smaller circle r =[tex]\frac{13.2}{2}=6.6\ mm[/tex]

Also, the radius of larger circle R= [tex]6.6+4.4=11.0\ mm[/tex]

Now, the area of the washer is given by :-

[tex]\text{Area of washer=Area of larger circle-Area of smaller circle}\\\\\Rightarrow\\text{Area of washer}=\pi R^2-\p r^2\\\\\Rightarrow\\text{Area of washer}=\pi(R^2-r^2)\\\\\Rightarrow\\text{Area of washer}=(3.14159265359)((11.0)^2-(6.6)^2)\\\\\Rightarrow\\text{Area of washer}=243.284935094\approx243.3\ mm^2[/tex]