For this case we have the following equation:
h (t) = -4.9t ^ 2 + 6t + 0.6
Deriving we have:
h '(t) = -9.8t + 6
We equal zero and clear t:
-9.8t + 6 = 0
9.8t = 6
t = 6 / 9.8
t = 0.61
We substitute the value of time in the equation of the height:
h (0.61) = -4.9 * (0.61) ^ 2 + 6 * (0.61) +0.6
h (0.61) = 2.44m
For the height to be higher than 2.44m, two values can be changed:
Initial speed: 6
Initial height: 0.6
Answer:
The maximum height of the ball is:
h (0.61) = 2.44m
You would have to change in the equation if the maximum height of the ball is more than 2.4 meters:
Initial speed: 6
or
Initial height: 0.6
