we can use the combined gas law equation to find the new temperature
[tex] \frac{P1V1}{T1} = \frac{P2V2}{T2} [/tex]
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
P - pressure
P1 - 0.925 atm x 101 325 Pa/atm = 93 726 Pa
P2 - 625 torr x 133 Pa/torr = 83 125 Pa
V - volume
V1 - 10.1 L
V2 - 12.2 L
T - temperature in kelvin
T1 - 25 °C + 273 = 298 K
substituting these values in the equation
[tex] \frac{93726Pa * 10.1L }{298K} = \frac{83125 Pa*12.2L}{T2} [/tex]
T = 319 K
temperature in celsius - 319 K - 273 = 46 °C
