A sheet of aluminum (al) foil has a total area of 1.000 ft2 and a mass of 3.716 g. what is the thickness of the foil in millimeters (density of al = 2.699 g/cm3)?
The mass of the sheet of aluminium is the product between its density d and its volume V: [tex]m=dV[/tex] Re-arranging the equation, we can find the volume of the sheet: [tex]V= \frac{m}{d}= \frac{3.716 g}{2.699 g/cm^3}= 1.377 cm^3[/tex]
Converted in millimeters, [tex]V=1377 mm^3[/tex]
The area is [tex]A=1.00 ft^2 [/tex] Since [tex]1 ft = 0.305 m[/tex], this area corresponds to [tex]A=1.00 ft^2 = (0.305 m)^2 = 0.093 m^2 = 0.093 \cdot 10^6 mm^2[/tex]
So we can now find the thickness of the sheet of aluminium: [tex]t= \frac{V}{A}= \frac{1377 mm^2}{0.093 \cdot 10^6 mm^2}=0.015 mm [/tex]
