First I drew a right triangle with the fountain on the opposite side of the angle 29.7. The engineer is 980 feet from the fountain, so th e bottom part of the triangle will be 980 ft. long. I used tangent because you have the adjacent and angle given to you, and you need to find the opposite side length of the angle (SOH CAH TOA - TOA is used here). I put that info. into an equation.
[tex] \tan(29.7) = opp \div 980[/tex]
I multiplied 980 on both sides to single out the opp. I then calculated the tangent of 29.7 with a calculator and multiplied it by 980. It came out to be 558.9821 ft. This rounded to the nearest ten feet is 560 feet.
