contestada

A gas is compressed from 600 cm3 to 200cm3 at a constant pressure of 400 kpa. at the same time, 100 j of heat energy is transferred out of the gas. part a what is the change in thermal energy of the gas during this process?

Respuesta :

skyluke89
The initial volume of the gas is
[tex]V_i = 600 cm^3[/tex]
while its final volume is
[tex]V_f = 200 cm^3[/tex]
so its variation of volume is
[tex]\Delta V = V_f - V-i = 200 cm^3 - 600 cm^3 = -400 cm^3 = -400 \cdot 10^{-6} m^3[/tex]

The pressure is constant, and it is
[tex]p=400 kPa = 400 \cdot 10^3 Pa[/tex]

Therefore the work done by the gas is
[tex]W=p\Delta V = (400 \cdot 10^3 Pa)(-400 \cdot 10^{-6} m^3)=-160 J[/tex]
where the negative sign means the work is done by the surrounding on the gas.

The heat energy given to the gas is
[tex]Q=+100 J[/tex]

And the change in internal energy of the gas can be found by using the first law of thermodynamics:
[tex]\Delta U = Q-W = 100 J - (-160 J)=+260 J[/tex]
where the positive sign means the internal energy of the gas has increased.

The change in thermal energy of the gas during this process is 260 Joules.

What is thermal energy?

When a body subjects to temperature, it gets heated up and its internal energy is increased . Thermal energy is the energy associated with the temperature of the body.

initial volume of the gas is  600 cm³,  final volume is 200cm³

The pressure is constant, p = 400 kPa.

Therefore the work done by the gas is

W = P(Vf -Vi)

W = 400x10³(-400x 10⁻⁶ m³) = -160J

The work is done by the surrounding on the gas.

The heat Q given to the gas = 100J

Using the first law of thermodynamics: ΔQ = ΔU +W

Substitute the values, we get

ΔU = 260 Joules.

Thus, the change in thermal energy of the gas during this process is 260 Joules.

Learn more about thermal energy.

https://brainly.com/question/11278589

#SPJ2

Otras preguntas