Respuesta :

Dejanras

Answer is:  2940 mL of the HCL solution.

c₁(HCl) = 10.0 M.

V₂(AgNO₃) = ?.
c₂(AgNO₃) = 0.85 M.
V₁(AgNO₃) = 250 mL ÷ 1000 mL/L = 0.25 L.

c₁ - original concentration of the solution, before it gets diluted.
c₂ - final concentration of the solution, after dilution.
V₁ - volume to be diluted.
V₂ - final volume after dilution.
c₁ · V₁ = c₂ · V₂.
V₂(HCl) = c₁ · V₁ ÷ c₂.

V₂(HCl) = 10 M · 0.25 L ÷ 0.85 M.

V₂(HCl) = 2.94 L · 1000 mL = 2940 mL.

kenmyna
The amount of 0.85M HCl solution that can  be made  by diluting 250 ml of 10M HCl is calculated using

M1V1=M2V2  formula

M1=0.85M
V1=?
M2= 10M
V2= 250 ml

by making the V1 the subject of the formula
V1 = M2V2/M1

V1 = (10 Mx250 ml)/ 0.85 M =2941.2 ml

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