Before answering the question, one should first calculate the pH for given concentration of LiOH.
As LiOH ionizes as,
LiOH → Li⁺ + OH⁻
So, the concentration of OH⁻ = [OH⁻] = 0.01
Also,
pOH = -log [OH⁻]
pOH = -log [0.01]
pOH = 2
Whereas,
POH + pH = 14
Or,
pH = 14 - 2
pH = 12
Result:
As pH is greater than 7, so the solution is Basic.