What is the concentration of AgCl in an aqueous solution that contains 1.2× 10^-3 gram of AgCl in 800. grams of the solution

Answer is: concentration of silver chloride is 1.5 ppm.

m(AgCl) = 1.2·10⁻³ g = 0.0012 g.
m(AgCl) = 0.0012 · 1000 mg/g.
m(AgCl) = 1.2 mg.
m(solution) = 800 g ÷ 1000 g/kg.
m(solution) = 0.8 kg.
concentration = 1.2 mg ÷ 0.8 kg = 1.5 mg/kg = 1.5 ppm.
Parts-per-million (10⁻⁶) is present at one-millionth of a gram per gram of sample solution, for example mg/kg.

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nikitarahangdaleVT nikitarahangdaleVT · Answer 2 · 2022-03-19T08:00:04+01:00

0.0104×10⁻³ m is the concentration of AgCl in an aqueous solution that contains 1.2× 10⁻³ gram of AgCl in 800. grams of the solution.

How we calculate concentration?

Here we calculate concentration in terms of molality, as no. of moles of solute present in per kilogram of the solvent.

Moles can be calculated as:

n = W/M, where

W = given mass

M = molar mass

Moles of AgCl in 1.2×10⁻³ gram = 1.2×10⁻³g / 143.32g/mol = 0.00837×10⁻³ mole

Given mass of solvent or water = 800g = 0.8kg

Concentration of AgCl (m) = 0.00837×10⁻³ / 0.8 = 0.0104×10⁻³ mol/kg

Hence, concentration of AgCl is 0.0104×10⁻³ mol/kg.

To know more about molality, visit the below link:

https://brainly.com/question/9149034