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The standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→li(s) −3.04 cl2(g)+2e−→2cl−(aq) +1.36 in a galvanic cell, the two half-reactions combine to 2li(s)+cl2(g)→2li+(aq)+2cl−(aq) calculate the cell potential of this reaction under standard reaction conditions. express your answer with the appropriate units. e∘ = submithintsmy answersgive upreview part

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kenmyna
  Li+(aq)   +e- →Li  (s)  - 3.04
 Cl2(g) + 2e- → 2Cl-(aq)  +1.36

     over  all  equation
2Li(s) + Cl2(g) →2  Li+(aq)  + 2Cl-(aq)
The  cell potential  of this  reaction  is + 4.40 V

        calculation
Ecell =E cathode - E  anode
E cathode is  = + 1.36 v
E  anode  is =  - 3.04 V

therefore  E   cell= 1.36 -(-3.04 ) =  4.40 V

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