Respuesta :

skyluke89
The energy of a photon is given by:
[tex]E=hf[/tex]
where h is the Planck constant and f is the photon frequency.
We know the energy of the photon, [tex]E=3.26 \cdot 10^{-19} J[/tex], so we can rearrange the equation to calculate the frequency of the photon:
[tex]f= \frac{E}{h}= \frac{3.26 \cdot 10^{-19}J}{6.6 \cdot 10^{-34}Js}=4.94 \cdot 10^{14}Hz [/tex]

And now we can use the following relationship between frequency f, wavelength [tex]\lambda[/tex] and speed of light c to find the wavelength of the photon:
[tex]\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{4.94 \cdot 10^{14} Hz}=6.07\cdot 10^{-7} m=607 nm [/tex]
snehashish65

The complete length of path covered by a wave in a second during its oscillation is known wavelength. The wavelength of the given wave is  [tex]6.07 \times 10^{-7} \;\rm m[/tex].

What is Wavelength?

At any point of wave propagation, the distance between the successive crests of the wave is known as the wavelength of the wave.

Given data -

The magnitude of wave energy is, [tex]E=3.26 \times 10^{-19} \;\rm J[/tex].

The relationship between frequency f, wavelength, and speed of light c to find the wavelength of the photon is,

[tex]\lambda = \dfrac{c}{f}[/tex]

The expression for the frequency of the wave is,

[tex]E= h \times f[/tex]

Here, h is Planck's constant.

Solving as,

[tex]E= h \times f\\\\3.26 \times 10^{-19} = (6.63 \times 10^{-34}) \times f \\\\f = 4.94 \times 10^{14} \;\rm Hz[/tex]

Now, the wavelength is calculated as,

[tex]\lambda = \dfrac{c}{f}\\\\\lambda = \dfrac{3 \times 10^{8}}{4.94 \times 10^{14}}\\\\\lambda = 6.07 \times 10^{-7} \;\rm m[/tex]

Thus, we can conclude that the wavelength of the wave is  [tex]6.07 \times 10^{-7} \;\rm m[/tex].

Learn more about the wavelength here:

https://brainly.com/question/7143261

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