Respuesta :
To find the complete ionic equation:
Consider:
Equation for the dissociation of the strong base in aqueous solution:
KOH (aq)------> K⁺(aq) + OH⁻(aq)
Equation for the dissociation of the strong acid in aqueous solution:
H₂SO₄(aq)------>2H⁺(aq) + SO₄²⁻(aq)
On the product' side, potassium sulfate that is a ionic compound:
K₂SO₄(aq)------>2K⁺ +SO₄²⁻
Water, a covalent compound:
So net balanced equation will be:
K⁺(aq) + OH⁻(aq) +2H⁺(aq) + SO₄²⁻(aq)------>2K⁺ + SO₄²⁻ +H₂O(l)
Net ionic equation by eliminating the spectator ions:
OH⁻(aq) +2H⁺(aq)-------->H₂O(l)
Answer : The complete ionic equation in separated aqueous solution will be,
[tex]2K^+(aq)+2OH^{-}(aq)+2H^{+}(aq)+SO_4^{2-}(aq)\rightarrow 2K^+(aq)+SO_4^{2-}(aq)+H_2O(l)[/tex]
Explanation :
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced molecular equation will be,
[tex]2KOH(aq)+H_2SO_4(aq)\rightarrow 2H_2O(l)+K_2SO_4(s)[/tex]
The complete ionic equation in separated aqueous solution will be,
[tex]2K^+(aq)+2OH^{-}(aq)+2H^{+}(aq)+SO_4^{2-}(aq)\rightarrow 2K^+(aq)+SO_4^{2-}(aq)+H_2O(l)[/tex]
