Calculate the mass percent composition of nitrogen in co(nh2)2.

The mass percentage composition of nitrogen in CO(NH2)2 is 46 .7%

calculation

% mass = molar mass of nitrogen/ molar mass of Co(NH2)2

molar mass of nitrogen = 14 x2 = 28g/mol since there is two nitrogen atom in Co(NH2)2\

molar mass of CO(NH2)2 = 12 + 16 + (14 x2) +( 2 x2)= 60 g/mol

the % mass is therefore =28 / 60 x100 =46.7%

Answer Link

Alleei Alleei · Answer 2 · 2019-10-21T16:48:28+02:00

Answer : The percent composition of nitrogen in [tex]CO(NH_2)_2[/tex] is, 46.7 %

Explanation : Given,

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of O = 16 g/mole

Molar mass of N = 14 g/mole

First we have to calculate the molar mass of [tex]CO(NH_2)_2[/tex] .

Molar mass of glucose [tex](CO(NH_2)_2[/tex] = [tex]1(12)+1(16)+2(14)+4(1)=60g/mole[/tex]

Now we have to calculate the mass percent composition of nitrogen in [tex]CO(NH_2)_2[/tex].

As we now that there are 1 number of carbon atom, 4 number of hydrogen atoms, 1 number of oxygen atom and 2 number of nitrogen atoms.

The mass of nitrogen = [tex]2\times 14=28g[/tex]

Formula used :

[tex]\%\text{ Mass percent composition of nitrogen}=\frac{\text{Mass of nitrogen}}{\text{Molar mass of } CO(NH_2)_2}\times 100[/tex]

Now put all the given values in this formula, we get:

[tex]\%\text{ Composition of nitrogen}=\frac{28}{60}\times 100=46.7\%[/tex]

Therefore, the percent composition of nitrogen in [tex]CO(NH_2)_2[/tex] is, 46.7 %