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Jillian wants to find the surface area of a pyramid. the base is a square with sides that are 4 inches long the other faces are isosceles triangles. the ratio of the height of each triangle to its base is 3:2. part a: give the Base length and the height of each triangular face part b : find the combined area of the Triangular faces part c: find the surface area of the pyramid

Respuesta :

Part a:-
The base of each triangle is 4 inches long. 
Their  height is 3/2 * 4 = 6 inches.

b 
The combined  area of the triangular faces = 4 * 1/2 * 4 * 6 =  48 sq ins

c
Surface area of the pyramid =  48 + area of base = 48 + 16  = 64 sq ins.
shubhamchouhanvrVT

Part a:-The base of each triangle is 4 inches long and their height is 3/2 * 4 = 6 inches.

Part b: The combined  area of the triangular faces 48 sq inches

Part c: The Surface area of the pyramid is 64 sq inches.

What is an area?

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Part a:-

The base of each triangle is 4 inches long.

Their  height is 3/2 x  4 = 6 inches.

Part b:-

The combined  area of the triangular faces = 4  x  1/2  x 4 x  6 =  48 sq ins

Part c:-

Surface area of the pyramid =  48 + area of base = 48 + 16  = 64 sq ins.

Therefore The base of each triangle is 4 inches long and their height is 3/2 * 4 = 6 inches. The combined area of the triangular faces is 48 sq inches. The Surface area of the pyramid is 64 sq inches.

To know more about an area follow

https://brainly.com/question/25292087

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