Answer:
The answer is B
m=45
n=12
Step-by-step explanation:
To solve for m and n we need to perform what we call matrix elements wise addition, which requires that we add elements off corresponding roll and columns
Step one
Let us start with m
To find m we will have trace it position,
it is in row 2 column 2
So we will add it to the Number in row 2 columns 2 of the second matrix and equate it to the row 2 columns 2 of the third matrix
Step two
Solving we have
m+3+(-8)=40
m+3-8=40
m-5=40
m=40+5
m=45
Step three
To solve for n we need to trace it position
n is in row one column one,
We add it to the in row one column one of the second matrix and equate it to the element in row one column one of the third matrix
Step four
Solving we have
n-1+(-1)=10
n-1-1=10
n-2=10
n=10+2
n=12
