Respuesta :

MarkV
Hi there!

[tex] - 4(8 - 3x) \geqslant 6x - 8[/tex]
First work out the parenthesis. Remember that a negative times a positive ends up with a negative. A negative times a negative ends up with a positive.

[tex] - 32 + 12x \geqslant 6x - 8[/tex]
Subtract 6x from both sides.

[tex] - 32 + 6x \geqslant - 8[/tex]
Add 32 to both sides.

[tex]6x \geqslant 24[/tex]
Divide both sides by 6.

[tex]x \geqslant 4[/tex]
Now we've found our solution.
~ Hope this helps you!

The solution to the given inequality is x≥4.

The given inequality is –4(8 – 3x) ≥ 6x – 8.

We need to find the solution to given inequality.

How do you solve inequality?

To solve an inequality, we can:

  • Add the same number to both sides.
  • Subtract the same number from both sides.
  • Multiply both sides by the same positive number.
  • Divide both sides by the same positive number.
  • Multiply both sides by the same negative number and reverse the sign.
  • Divide both sides by the same negative number and reverse the sign.

Now, in the inequality –4(8 – 3x) ≥ 6x – 8.

Isolate the variable by dividing or multiplying each side by factors that don't contain the variable.

That is, -32 +12x ≥ 6x – 8

⇒12x≥6x+24

⇒6x≥24

⇒x≥4

Inequality Form: x≥4

Interval notation: [4, ∞)

Therefore, the solution to the given inequality is x≥4.

To learn more about the inequalities visit:

https://brainly.com/question/20383699.

#SPJ6

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