Respuesta :
[tex]f(x)=2x+1\to y=2x+1\\\\\text{We solve for x}\\\\2x+1=y\ \ \ |-1\\\\2x=y-1\ \ \ |:2\\\\x=\dfrac{y-1}{2}\to x=\dfrac{1}{2}y-\dfrac{1}{2}[/tex]
[tex]\text{Answer:}\ f^{-1}(x)=\dfrac{1}{2}x-\dfrac{1}{2}[/tex]
[tex]\text{Answer:}\ f^{-1}(x)=\dfrac{1}{2}x-\dfrac{1}{2}[/tex]
Answer:
h(x) = 1/2x - 1/2
Step-by-step explanation:
I took the EDGE test and it was correct