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apologiabiology
point slope form is [tex](y-y_1)=m(x-x_1)[/tex] where [tex](x_1,y_1)[/tex] are a point that the line passes through and [tex] m [/tex] is the slope
I guess solve for 1 y and get the constants to the left side3y=x+11divide both sides by 3[tex]y=\frac{1}{3}(x+11)[/tex]there you have it:[tex]y-0=\frac{1}{3}(x-(-11))[/tex]it passes through the point (-11,0) and has a slope of 1/3
AnimeBrainly

Slope formula is y = mx + b

Isolate the y. Divide 3 from both sides

3y = x + 11

(3y)/3 = (x + 11)/3

y = (x + 11)/3

Set y = 0.

0 = (1x + 11)/3

Slope = 1/3

Solve for x.

0(3) = (x + 11)/3(3)

0 = x + 11

0 (-11) = x + 11 (-11)

x = 0 - 11

x = 11

hope this helps

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