So with this polygon, you're gonna have to break it into 3 pieces: square VEDR, triangle MVA, and triangle MRA (point A is at (-2,2). I gave it a point so its easier to explain). And then you're gonna get those areas and then add them together.
Starting with the square:
Sides ED and VR are 6 units.
Sides VE and RD are 5 units.
Area of a square is [tex]A=bh[/tex], so just plug in 6 and 5 in there to get 30 units^2
Now triangle MVA:
Side MA is 3 units.
Side AV is 1 unit.
Area of a triangle is [tex]A= \frac{1}{2}bh[/tex] . Plug in 3 and 1 at the b and h variable and solve. Your answer should be 1.5 units^2.
Finally, triangle MRA:
Side MA has 3 units, as previously mentioned.
Side AR has 5 units.
Area of a triangle is [tex]A= \frac{1}{2}bh[/tex] . Plug in 3 and 5 at the b and h variable and solve. Your answer should be 7.5 units^2.
Now the adding part:
The areas we have gotten are 30, 1.5, and 7.5. Add them all up to get 39 units^2, which is the area of the polygon.
