Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. The roots of an equation are x = -1 ± i. The equation is x2 + + 2 = 0.

Respuesta :

If those are your roots, in factorization form they are [x-(-1+i)][x-(-1-i)], which simplifies to (x+1-i)(x+1+i).  FOIL that out like you would anything else to get the mess that looks like this: [tex] x^{2} +x+ix+x+1+i-ix-i- i^{2} [/tex].  Putting things in order makes it easier to deal with.  [tex] x^{2} +x+x+ix-ix+i-i+1- i^{2} [/tex].  Canceling out what we can, gives us [tex] x^{2} +2x+1- i^{2} [/tex]. [tex] i^{2}=-1 [/tex].  That simplifies to [tex] x^{2} +2x+1-(-1)[/tex], which of course gives us [tex] x^{2} +2x+1+1[/tex] and [tex] x^{2} +2x+2[/tex] is the final result.  Your missing term there is 2x

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