For Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:
[tex]p_1 = p_2[/tex]
which becomes
[tex] \frac{F_1}{A_1}= \frac{F_2}{A_2} [/tex]
where
[tex]F_1=3600 N[/tex] is the force on the first piston
[tex]A_1=0.030 m^2[/tex] is the area of the first piston
[tex]F_2[/tex] is the force on the second piston
[tex]A_2=0.015 m^2[/tex] is the area of the second piston
If we rearrange the equation and we use these data, we can find the intensity of the force on the second piston:
[tex]F_2=F_1 \frac{A_2}{A_1}=(3600 N) \frac{0.015 m^2}{0.030 m^2}= 1800 N[/tex]
