Respuesta :
At STP, 1 mole has occupies a volume of 22.4 L. So n = 1. We have 45.0L of gas at 100 kPa and 373 K we plug in these given values of V, R, P and T to the ideal gas law equation: PV = nRT and solve for n. (We use 8.314 L kPa/ mol*K as the gas constant). The n value we got is 1.45, exceeding the 1 mole minimum requirement.
Thus the answer is: "You will have an excess of gas and the reaction will occur. "
See if you get more than 1 mole or less.
Thus the answer is: "You will have an excess of gas and the reaction will occur. "
See if you get more than 1 mole or less.
Calculated moles of gas for the given reaction is 1.45 moles which is in excess as compare to the standard moles of gas.
What is ideal gas equation?
We will calculate the moles of gas using the Ideal gas equation as:
PV = nRT, where
P = pressure of gas = 100kPa
V = volume of gas = 45L
R = universal gas constant = 8.3 L.kPa/mol.K
T = temperature of gas = 373K
n = moles of gas = to find?
On putting all these values on the above equation and calculate for n as:
n = (100×45) / (8.3×373) = 1.45 moles
In the question given that reaction requires 22.4L gas at STP, and at this condition no. of moles of gas is 1. And the calculated moles of gas is 1.4 which is more than 1 mole and sufficient for the reaction.
Hence, calculated moles of gas is more than standard moles.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/3778152
