The gravitational potential energy gained by Tim is given by the following equation:
[tex]\Delta U = mg \Delta h[/tex]
where
m is Tim's mass
g is the gravitational acceleration
[tex]\Delta h[/tex] is the vertical distance covered by Tim
If we substitute the data given by the problem into the equation, we find how much potential energy Tim has gained:
[tex]\Delta U=(79.8 kg)(9.81 m/s^2)(5.3 m)=4149 J[/tex]
