Respuesta :
According to Avagadro's constant 1 mole of a substance contains 6.022× 10^23 particles (molecules, atoms or ions).
1 mole of CH4O contains 32 g
therefore; 32 g of CH4O is equivalent to 1 mole;
Hence; 32 grams of CH4O contains 6.022 ×10^23 molecules.
1 mole of CH4O contains 32 g
therefore; 32 g of CH4O is equivalent to 1 mole;
Hence; 32 grams of CH4O contains 6.022 ×10^23 molecules.
Answer: A sample of [tex]CH_4O[/tex] will contain [tex]6.022\times 10^{23}[/tex] number of molecules
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Given mass of [tex]CH_4O[/tex] = 32.0 g
Molar mass of [tex]CH_4O[/tex] = 32 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of }CH_4O=\frac{32.0g}{32g/mol}=1mol[/tex]
According to mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of molecules
Hence, a sample of [tex]CH_4O[/tex] will contain [tex]6.022\times 10^{23}[/tex] number of molecules
