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Consider the reaction n2 + 3 h2 → 2 nh3 . how much nh3 can be produced from the reaction of 74.2 g of n2 and 14.0 moles of h2? 1. 1.26 × 1025 molecules 2. 1.59 × 1024 molecules 3. 3.19 × 1024 molecules 4. 5.62 × 1024 molecules 5. 1.69 × 1025 molecules

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JoshEast
Reaction:   N₂   +   3 H₂   →   2 NH₃  

the mole ratio of  H₂  :   NH₃    is    3  :   2

If the number of moles of H₂ is 14.0 mol
    then the number of moles of NH₃ = (14.0 mol ÷  3) × 2
                                                            =  9.33 mol

Now, the number of molecules = moles  ×  Avogadro's Constant
                                                     =  9.33 mol × (6.02 × 10²³)
                                                     =  5.6187 × 10²⁴  molecules

As such the answer is 5.62 × 10²⁴  molecules [OPTION 4]       
                                                                

The stoichiometry coefficient is used to determine the number of molecules and moles. 5.62 × 10²⁴ molecules of ammonia are produced in the reaction. Thus, option 4 is correct.

What are molecules?

Molecules are the group of atoms that are given as the product of the moles and the Avogadro's number.

The balanced chemical reaction is given as:

N₂ + 3 H₂ → 2 NH₃  

From the reaction, it can be deduced that 3 moles of dihydrogen will produce 2 moles of ammonia.

From the question the moles of dihydrogen are 14 moles so, the moles of ammonia are:

(14 × 2) ÷ 3 = 9.33 moles

Molecules of ammoina = moles × Avogadro's Constant

= 9.33 mol × (6.02 × 10²³)

= 5.6187 × 10²⁴ molecules

Therefore, option 4. 5.6187 × 10²⁴ molecules of ammonia are produced.

Learn more about molecules here:

https://brainly.com/question/13916365

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