See the attached figure which represents the explanation of the problem.
Let the height of the building = h
∵ ∠1 congruent to ∠2
∴ ∠1 = ∠2
∴ tan (∠1) = tan (∠2) ⇒⇒⇒ tan of the angle = (opposite/adjacent)
∴ [tex] \frac{5}{12} = \frac{h}{264} [/tex]
∴ 12 h = 5 * 264 = 1,320
∴ h = 1,320/12 = 110 feet
∴ The height of the building = 110 feet